Zastaralý přístup s FROM OPENXML
tady by mohla být možnost. Zkontrolujte tuto odpověď
.
Na tomto odkazu najdete funkci, kterou čas od času zveřejňuje John Cappelletti, která skartuje jakékoli XML (kredity pod kódem funkce).
Ale nejsem si jistý, čeho se vlastně snažíš dosáhnout... Proč potřebuješ cestu? Pokud vás zajímají hodnoty všech cílových uzlů, můžete udělat něco takového (hloubkové vyhledávání pomocí //
nepotřebuje přesnou XPath
)
SELECT t.value(N'(text())[1]','nvarchar(max)')
FROM @xml.nodes('//target') AS A(t);
Pokud opravdu potřebujete vše a všechno můžete zkontrolovat toto:
CREATE FUNCTION [dbo].[udf-XML-Hier](@XML xml)
Returns Table
As Return
with cte0 as (
Select Lvl = 1
,ID = Cast(1 as int)
,Pt = Cast(NULL as int)
,Element = x.value('local-name(.)','varchar(150)')
,Attribute = cast('' as varchar(150))
,Value = x.value('text()[1]','varchar(max)')
,XPath = cast(concat(x.value('local-name(.)','varchar(max)'),'[' ,cast(Row_Number() Over(Order By (Select 1)) as int),']') as varchar(max))
,Seq = cast(1000000+Row_Number() over(Order By (Select 1)) as varchar(max))
,AttData = x.query('.')
,XMLData = x.query('*')
From @XML.nodes('/*') a(x)
Union All
Select Lvl = p.Lvl + 1
,ID = Cast( (Lvl + 1) * 1024 + (Row_Number() Over(Order By (Select 1)) * 2) as int ) * 10
,Pt = p.ID
,Element = c.value('local-name(.)','varchar(150)')
,Attribute = cast('' as varchar(150))
,Value = cast( c.value('text()[1]','varchar(max)') as varchar(max) )
,XPath = cast(concat(p.XPath,'/',c.value('local-name(.)','varchar(max)'),'[',cast(Row_Number() Over(PARTITION BY c.value('local-name(.)','varchar(max)') Order By (Select 1)) as int),']') as varchar(max) )
,Seq = cast(concat(p.Seq,' ',10000000+Cast( (Lvl + 1) * 1024 + (Row_Number() Over(Order By (Select 1)) * 2) as int ) * 10) as varchar(max))
,AttData = c.query('.')
,XMLData = c.query('*')
From cte0 p
Cross Apply p.XMLData.nodes('*') b(c)
)
, cte1 as (
Select R1 = Row_Number() over (Order By Seq),A.*
From (
Select Lvl,ID,Pt,Element,Attribute,Value,XPath,Seq From cte0
Union All
Select Lvl = p.Lvl+1
,ID = p.ID + Row_Number() over (Order By (Select NULL))
,Pt = p.ID
,Element = p.Element
,Attribute = x.value('local-name(.)','varchar(150)')
,Value = x.value('.','varchar(max)')
,XPath = p.XPath + '/@' + x.value('local-name(.)','varchar(max)')
,Seq = cast(concat(p.Seq,' ',10000000+p.ID + Row_Number() over (Order By (Select NULL)) ) as varchar(max))
From cte0 p
Cross Apply AttData.nodes('/*/@*') a(x)
) A
)
Select A.R1
,R2 = IsNull((Select max(R1) From cte1 Where Seq Like A.Seq+'%'),A.R1)
,A.Lvl
,A.ID
,A.Pt
,A.Element
,A.Attribute
,A.XPath
,Title = Replicate('|---',Lvl-1)+Element+IIF(Attribute='','','@'+Attribute)
,A.Value
From cte1 A
/*
Source: http://beyondrelational.com/modules/2/blogs/28/posts/10495/xquery-lab-58-select-from-xml.aspx
Taken from John Cappelletti: https://stackoverflow.com/a/42729851/5089204
Declare @XML xml='<person><firstname preferred="Annie" nickname="BeBe">Annabelle</firstname><lastname>Smith</lastname></person>'
Select * from [dbo].[udf-XML-Hier](@XML) Order by R1
*/
GO
DECLARE @xml XML=
'<log>
<clients>
<client>
<section name ="Apps">
<questions>
<groupone>
<question>
<target>Age</target>
</question>
<question>
<target> Height</target>
</question>
<question>
<target> Weight</target>
</question>
</groupone>
<grouptwo name = "exercise">
<wording>what is your name</wording>
<question>
<id>1</id>
<target>def</target>
</question>
</grouptwo>
</questions>
</section>
</client>
</clients>
</log>';
SELECT * FROM dbo.[udf-XML-Hier](@xml);
GO