Všechny možné kombinace pro data dvou sloupců

Zde je jeden způsob.

Teoreticky si poradí až s 20 tagy na produkt (omezeno velikostí číselné tabulky), ale o to jsem se neobtěžoval. Na mé ploše trvalo asi 30 sekund, než jsem vychrlil 65 535 výsledků pro jeden produkt se 16 značkami. Doufejme, že váš skutečný počet značek na produkt bude mnohem menší!

IF OBJECT_ID('tempdb..#Nums') IS NULL
BEGIN
CREATE TABLE #Nums
(
i int primary key
)

;WITH 
L0 AS (SELECT 1 AS c UNION ALL SELECT 1),       
L1 AS (SELECT 1 AS c FROM L0 A CROSS JOIN L0 B), 
L2 AS (SELECT 1 AS c FROM L1 A CROSS JOIN L1 B), 
L3 AS (SELECT 1 AS c FROM L2 A CROSS JOIN L2 B),
L4 AS (SELECT 1 AS c FROM L3 A CROSS JOIN L3 B), 
L5 AS (SELECT 1 AS c FROM L4 A CROSS JOIN L4 B), 
Nums AS (SELECT ROW_NUMBER() OVER (ORDER BY (SELECT 0)) AS i FROM L5)

INSERT INTO #Nums
SELECT TOP 1048576 i FROM Nums;
END


;with ProductTags As
(
SELECT 1 ProductId,'Leather' AS Tag UNION ALL
SELECT 1, 'Watch' UNION ALL
SELECT 2, 'Red' UNION ALL
SELECT 2, 'Necklace' UNION ALL
SELECT 2, 'Pearl'
), NumberedTags AS
(
SELECT 
      ProductId,Tag,
       ROW_NUMBER() OVER (PARTITION BY ProductId ORDER BY Tag) rn,
       COUNT(*) OVER (PARTITION BY ProductId) cn
FROM ProductTags
),
GroupedTags As
(
SELECT ProductId,Tag,i
FROM NumberedTags
JOIN #Nums  on 
               #Nums.i <  POWER ( 2 ,cn)  
           and #Nums.i & POWER ( 2 ,rn-1) > 0
)
SELECT ProductId, 
       STUFF((SELECT CAST(', ' + Tag AS VARCHAR(MAX)) 
          FROM GroupedTags g2
         WHERE g1.ProductId = g2.ProductId and g1.i = g2.i
      ORDER BY Tag
       FOR XML PATH ('')),1,1,'') AS Tags
FROM GroupedTags g1
GROUP BY ProductId, i
ORDER BY ProductId, i

Vrátí

ProductId   Tags
----------- ------------------------------
1            Leather
1            Watch
1            Leather, Watch
2            Necklace
2            Pearl
2            Necklace, Pearl
2            Red
2            Necklace, Red
2            Pearl, Red
2            Necklace, Pearl, Red