Zkuste tento dotaz, poskytne vám každý trénink a nejnovější historii tréninku pro každý z nich:
SELECT tc.id, tc.name, tc.order,
th.id as history_id, th.finished_at, th.score
FROM trainings tc
LEFT OUTER JOIN training_histories th ON th.training_id = tc.id
and th.id =
(SELECT th1.id from training_histories th1 where th1.training_id = tc.id
and th1.finished_at is not null
order by th1.finished_at desc limit 1)
WHERE tc.id > 4
AND tc.id < 8
GROUP BY tc.id
ORDER BY tc.order_by ASC, tc.id ASC