Zdá se, že se o to pokoušíte:
select d.RepName,
count(d.RepName) DoctorReportsCount,
count(h.RepName) HospitalsReportsCount,
d.DateAdded
from doctorreports d
inner join hospitals h
on d.RepName = h.RepName
group by d.RepName, d.DateAdded
upravit:
select *
from
(
select d.RepName,
count(d.RepName) DoctorReportsCount
, d.dateadded
from doctorreports d
group by d.RepName, d.dateadded
) d
left join
(
select h.RepName,
count(h.RepName) HospitalsReportsCount
, h.dateadded hDateadded
from hospitals h
group by h.RepName, h.dateadded
)h
on d.RepName = h.RepName
viz SQL Fiddle s ukázkou
edit #2, pokud chcete vrátit data pro dny, které chybí, pak bych doporučil vytvořit tabulku obsahující kalendářní data, pak můžete vrátit data pro dny, které chybí. Následující by vám mělo vrátit to, co hledáte. Pro tento dotaz jsem vytvořil kalendářní tabulku:
select COALESCE(d.drep, '') repname,
COALESCE(d.DCount, 0) DoctorReportsCount,
COALESCE(h.HCount, 0) HospitalsReportsCount,
c.dt Dateadded
from calendar c
left join
(
select repname drep,
count(repname) DCount,
dateadded ddate
from doctorreports
group by repname, dateadded
) d
on c.dt = d.ddate
left join
(
select repname hrep,
count(repname) HCount,
dateadded hdate
from hospitals
group by repname, dateadded
) h
on c.dt = h.hdate
and d.drep = h.hrep
viz SQL Fiddle s ukázkou
Pokud vás ostatní data nezajímají, takto byste to udělali bez date
tabulka:
select COALESCE(d.RepName, '') repname,
COALESCE(d.DoctorReportsCount, 0) DoctorReportsCount,
COALESCE(h.HospitalsReportsCount, 0) HospitalsReportsCount,
COALESCE(p.PharmacyReportsCount, 0) PharmacyReportsCount,
d.dateadded Dateadded
from
(
select d.RepName,
count(d.RepName) DoctorReportsCount
, d.dateadded
from doctorreports d
group by d.RepName, d.dateadded
) d
left join
(
select h.RepName,
count(h.RepName) HospitalsReportsCount
, h.dateadded hDateadded
from hospitals h
group by h.RepName, h.dateadded
)h
on d.RepName = h.RepName
and d.dateadded = h.hDateadded
left join
(
select p.RepName,
count(p.RepName) PharmacyReportsCount
, p.dateadded hDateadded
from PharmacyReports p
group by p.RepName, p.dateadded
)p
on d.RepName = p.RepName
and d.dateadded = p.hDateadded