nelze podmíněně vytvářet spojení napříč tabulkami. Nejlepší způsob, jak to udělat, je použít LEFT JOIN
a použijte CASE
ve vašem SELECT
prohlášení. Musíte zadat běžné sloupce, které chcete zobrazit,
SELECT *,
(CASE notification_base.type
WHEN 'photo'
THEN photo.columnName1
ELSE post.ColumnName1
END) as ColumnName1,
(CASE notification_base.type
WHEN 'photo'
THEN photo.columnName2
ELSE post.ColumnName2
END) as ColumnName2
FROM notification_action
INNER JOIN notification_base
ON notification_action.not_base_id = notification_base.id
INNER JOIN notification_sub
ON notification_action.not_base_id = notification_sub.not_base_id
INNER JOIN photo
ON photo.id = notification_base.object_id
INNER JOIN post
ON post.id = notification_base.object_id
WHERE notification_sub.user_id = 3
AND notification_sub.lastShowDate < notification_action.creationDate;