Nejprve musíte projít stromem nahoru, abyste získali všechny manažery, a poté dolů, abyste získali všechny zaměstnance:
select level, employee_id, last_name, manager_id ,
connect_by_root employee_id as root_id
from employees
connect by prior employee_id = manager_id -- down the tree
start with manager_id in ( -- list up the tree
select manager_id
from employees
connect by employee_id = prior manager_id -- up the tree
start with employee_id = 101
)
;
Viz http://www.sqlfiddle.com/#!4/d15e7/18
Upravit:
Pokud daný uzel může být také kořenovým uzlem, rozšiřte dotaz tak, aby zahrnoval daný uzel v seznamu nadřazených uzlů:
Příklad pro nekořenový uzel:
select distinct employee_id, last_name, manager_id
from employees
connect by prior employee_id = manager_id -- down the tree
start with manager_id in ( -- list up the tree
select manager_id
from employees
connect by employee_id = prior manager_id -- up the tree
start with employee_id = 101
union
select manager_id -- in case we are the root node
from employees
where manager_id = 101
)
;
Příklad pro kořenový uzel:
select distinct employee_id, last_name, manager_id
from employees
connect by prior employee_id = manager_id -- down the tree
start with manager_id in ( -- list up the tree
select manager_id
from employees
connect by employee_id = prior manager_id -- up the tree
start with employee_id = 100
union
select manager_id -- in case we are the root node
from employees
where manager_id = 100
)
;
Fiddle na http://www.sqlfiddle.com/#!4/d15e7/32