Stejně jako vyberete COUNT(Customer_Nbr)
v 1. dílčím dotazu jej vyberte také v 2. dílčím dotazu:
SELECT Entity_Name,
COUNT(Customer_Nbr) AS `Total Customer`,
SUM(CASE WHEN Payment_Mode = 'Online Payment' THEN Amount ELSE 0 END) AS `Online Payment`,
SUM(CASE WHEN Payment_Mode = 'Cash' THEN Amount ELSE 0 END) AS `Cash Payment`,
SUM(Amount) AS `Total Payment`
FROM mq_paymentlist
GROUP BY Entity_Name
a v hlavním dotazu použijte GREATEST()
vyberte maximální hodnotu:
SELECT b.Entity_Name,
GREATEST(b.`Total Customer`, p.`Total Customer`) AS `Total Customer`
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